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9x^2+30=33x
We move all terms to the left:
9x^2+30-(33x)=0
a = 9; b = -33; c = +30;
Δ = b2-4ac
Δ = -332-4·9·30
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-3}{2*9}=\frac{30}{18} =1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+3}{2*9}=\frac{36}{18} =2 $
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